$\dfrac{5x + 4}{6}$`-`$\dfrac{8x - 1}{3}$`=`$\dfrac{4x + 1 }{5 + 2}$

2 câu trả lời

`(5x+4)/6-(8x-1)/3=(4x+1)/(5+2)`

`<=>(5x+4)/6-(8x-1)/3=(4x+1)/7`

`<=>(7(5x+4))/42-(14(8x-1))/42=(6(4x+1))/42`

`=>7(5x+4)-14(8x-1)=6(4x+1)`

`<=>(35x+28)-(112x-14)=24x+6`

`<=>35x+28-112x+14=24x+6`

`<=>35x-112x-24x=6-28-14`

`<=> -101x=-36`

`<=>x=36/101`

Vậy `S={36/101}`

$\dfrac{5x+4}{6}-\dfrac{8x-1}{3}=\dfrac{4x+1}{5+2}$

$⇔ \dfrac{5x+4}{6}-\dfrac{8x-1}{3}=\dfrac{4x+1}{7}$

$⇔ \dfrac{7(5x+4)}{6.7}-\dfrac{14(8x-1)}{3.14}=\dfrac{6(4x+1)}{7.6}$

$⇔ \dfrac{35x+28}{42}-\dfrac{112x-14}{42}=\dfrac{24x+6}{42}$

$⇒  35x+28-(112x-14)=24x+6$

$⇔ 35x+28-112x+14=24x+6$

$⇔ -77x+42=24x+6$

$⇔ -77x-24x=-42+6$

$⇔ -101x=-36$

$⇔ x=\dfrac{36}{101}$

Vậy phương trình có tập nghiệm `S={36/101}`

$#thanhmaii2008$

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