√4x^2-12x+9=x+5 Chỉ mình cảm ơn 😷

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$\text{Vì không hiểu đề nên mình làm hai cách}$

`\sqrt{4x^2-12x+9}=x+5`

`⇔\sqrt{(2x)^2-2.2x.3+3^2)=x+5`

`⇔\sqrt{(2x-3)^2}=x+5`

`⇔|2x-3|=x+5`

\(\left[ \begin{array}{l}2x-3=x+5\\3-2x=x+5\end{array} \right.\)

\(\left[ \begin{array}{l}2x-x=3+5\\2x+x=3-5\end{array} \right.\)

\(\left[ \begin{array}{l}x=8\\3x=-2\end{array} \right.\)

\(\left[ \begin{array}{l}x=8(tm)\\x=-\dfrac{2}{3}(tm)\end{array} \right.\)

$\text{Vậy}$ `x∈{8;-2/3}`

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`\sqrt{4x^2}-12x+9=x+5`

`⇔\sqrt{(2x)^2}=x+5+12x-9`

`⇔|2x|=13x-4`

`⇔2x=±(13x-4)`

\(\left[ \begin{array}{l}2x=13x-4\\2x=4-13x\end{array} \right.\)

\(\left[ \begin{array}{l}13x-2x=4\\13x+2x=4\end{array} \right.\)

\(\left[ \begin{array}{l}11x=4\\15x=4\end{array} \right.\)

\(\left[ \begin{array}{l}x=\dfrac{4}{11}(tm)\\x=\dfrac{4}{15}(tm)\end{array} \right.\)

$\text{Vậy}$ `x∈{4/11;4/15}`