2 câu trả lời
(2x+1)3−8(x+2)(x2−2x+4)
=8x3+3.4x2+3.2x+1−8(x3−2x2+4x+2x2−4x+8)
=8x3+12x2+6x+1−8x3+16x2−32x−16x2+32x−64)
=12x2+6x−63
(2x+1)3−8(x+2)(x2−2x+4)
=8x3+3.4x2+3.2x+1−8(x3−2x2+4x+2x2−4x+8)
=8x3+12x2+6x+1−8x3+16x2−32x−16x2+32x−64)
=12x2+6x−63
Câu hỏi trong lớp
Xem thêm