Khi nhiệt phân hoàn toàn 100 gam mỗi chất sau: KClO₃ (xúc tác MnO₂), KMnO₄, KNO₃ và AgNO₃. Chất tạo ra lượng O₂  lớn nhất là

$KCl{O_3}\xrightarrow{{{t^o},Mn{O_2}}}KCl\,\,\,\, + \,\,\,\frac{3}{2}{O_2} \uparrow $

$ \to {n_{{O_2}}} = \frac{3}{2}{n_{KCl{O_3}}} = \frac{3}{2} \cdot \frac{{100}}{{122,5}} \approx 1,224\,mol$

$2KMn{O_4}\xrightarrow{{{t^o}}}{K_2}Mn{O_4}\,\,\, + \,\,\,\,Mn{O_2}\,\,\,\, + \,\,\,{O_2}$$ \uparrow $

$ \to {n_{{O_2}}} = \frac{1}{2}{n_{KMn{O_4}}} = \frac{1}{2} \cdot \frac{{100}}{{158}} \approx 0,316\,mol$

$KN{O_3}\xrightarrow{{{t^o}}}KN{O_2}\,\,\,\, + \,\,\,\frac{1}{2}{O_2}$$ \uparrow $

$ \to {n_{{O_2}}} = \frac{1}{2}{n_{KN{O_3}}} = \frac{1}{2} \cdot \frac{{100}}{{101}} \approx 0,495mol$

$AgN{O_3}\xrightarrow{{{t^o}}}Ag\,\,\,\,\, + \,\,\,\,N{O_2}\,\,\,\, + \,\,\,\frac{1}{2}{O_2}$$ \uparrow $

$ \to {n_{{O_2}}} = \frac{1}{2}{n_{AgN{O_3}}} = \frac{1}{2} \cdot \frac{{100}}{{170}} \approx 0,294mol$