Kết quả của phép chia $\left( {6x{y^2} + 4{x^2}y - 2{x^3}} \right):2x$ là

${\left( {{x^4} - 2} \right)^2} - {\left( {2{x^2}} \right)^2}$.

${\left( {{x^4} + 4} \right)^2} - {\left( {4{x^2}} \right)^2}$.

${\left( {{x^4} + 2} \right)^2} - {\left( {4{x^2}} \right)^2}$.

${\left( {{x^4} + 2} \right)^2} - {\left( {2{x^2}} \right)^2}$.

${\left( {3x - 2y} \right)^2} - {\left( {2x - 3y} \right)^2} = 5\left( {x - y} \right)\left( {x + y} \right)$.

${\left( {3x - 2y} \right)^2} - {\left( {2x - 3y} \right)^2} = \left( {5x - y} \right)\left( {x - 5y} \right)$.

${\left( {3x - 2y} \right)^2} - {\left( {2x - 3y} \right)^2} = \left( {x - y} \right)\left( {x + y} \right)$.

${\left( {3x - 2y} \right)^2} - {\left( {2x - 3y} \right)^2} = 5\left( {x - y} \right)\left( {x - 5y} \right)$.

$2x - 3;5x - 5$.

$2x - 3; - 5x + 1$.

$- 5x + 1;2x - 3$.      

$2x - 3; - 5x - 5$.

$- \dfrac{{11}}{7}$  

$\dfrac{7}{{11}}$

$1$

$\dfrac{{11}}{7}$

$2$.

$3$.

$1$.

$4$.

${\left( {{x^2}} \right)^3} + {3^3}$.

${\left( {{x^2}} \right)^3} - {3^3}$.

${\left( {{x^2}} \right)^3} + {9^3}$.

${\left( {{x^2}} \right)^3} - {9^3}$.