Cho $n = 2k + 1,k \in N$. Khi đó:

$\mathop {\lim }\limits_{x \to  + \infty } f\left( x \right) = L$

$\mathop {\lim }\limits_{x \to  - \infty } f\left( x \right) = L$

$\mathop {\lim }\limits_{x \to {x_0}} f\left( x \right) = L$

$\mathop {\lim }\limits_{x \to L} f\left( x \right) = {x_0}$

$\dfrac{1}{5}.$

$\sqrt 5 .$

$\dfrac{1}{{\sqrt 5 }}.$

$5.$

$\mathop {\lim }\limits_{x \to {x_0}} \left[ {f\left( x \right) + g\left( x \right)} \right] = L$

$\mathop {\lim }\limits_{x \to {x_0}} \left[ {f\left( x \right) + g\left( x \right)} \right] = M$

$\mathop {\lim }\limits_{x \to {x_0}} \left[ {f\left( x \right) + g\left( x \right)} \right] = L - M$                           

$\mathop {\lim }\limits_{x \to {x_0}} \left[ {f\left( x \right) + g\left( x \right)} \right] = M + L$

$0.$

$1.$

$2.$

$3.$

$\mathop {\lim }\limits_{x \to x_0^ + } f\left( x \right) = L$           

$\mathop {\lim }\limits_{x \to x_0^ - } f\left( x \right) = L$

$\mathop {\lim }\limits_{x \to  + \infty } f\left( x \right) = L$

$\mathop {\lim }\limits_{x \to  - \infty } f\left( x \right) = L$

$1.$

$- \infty .$

$0.$

$+ \infty .$

$\mathop {\lim }\limits_{x \to x_0^ + } f\left( x \right) = L$

$\mathop {\lim }\limits_{x \to x_0^ + } f\left( x \right) =  - L$        

$\mathop {\lim }\limits_{x \to x_0^ - } f\left( x \right) =  - L$

$\mathop {\lim }\limits_{x \to x_0^ + } f\left( x \right) = - \mathop {\lim }\limits_{x \to x_0^ - } f\left( x \right)$