Bất phương trình $2(x - 1) - x > 3(x - 1) - 2x - 5$ có nghiệm là:

$m \ne 1$       

$m \ne  - \dfrac{1}{3}$

$m \ne 0$       

$m \ne 8$.

\(x = \dfrac{1}{3}\)                

\(x = 1,5;x = \dfrac{{ - 1}}{3}\)              

\(x =  - 1,5;x = \dfrac{{ - 1}}{3}\)           

\(x = 1,5;x = \dfrac{1}{3}\)

$5x + 7 < 0$                    

$0x + 6 > 0$

${x^2} - 2x > 0$                           

$x - 10 = 3$.

$x > \dfrac{3}{5}$     

$x \le  - \dfrac{5}{3}$

$x \ge  - \dfrac{5}{3}$           

$x >  - \dfrac{5}{3}$.

\(2x + 1 > 5\)

 \(7 - 2x < 10 - x\)

\(2 + x < 2 + 2x\)

\( - 3x > 4x + 3\)

$7 - x < 2x$

$2x + 3 > 9$

$ - 4x \ge x + 5$

$5 - x > 6x - 12$

$S = \left\{ {x|x > 1} \right\}$

$S = \left\{ {x|x > -1} \right\}$

$x = 1$

$S = \left\{ {x|x < 1} \right\}$