2 câu trả lời
`sqrt{(x^2-2x+1)}-6=0`
`=>sqrt{(x-1)^2}=6`
`=>sqrt{(x-1)^2}=6`
`=>|x-1|=6`
`=>`\(\left[ \begin{array}{l}x-1=6\\x-1=-6\end{array} \right.\)
`=>`\(\left[ \begin{array}{l}x=7\\x=-5\end{array} \right.\)
Vậy `S={7;-5}`
`sqrt{(x^2-2x+1)}-6=0`
`=>sqrt{(x-1)^2}=6`
`=>sqrt{(x-1)^2}=6`
`=>|x-1|=6`
`=>`\(\left[ \begin{array}{l}x-1=6\\x-1=-6\end{array} \right.\)
`=>`\(\left[ \begin{array}{l}x=7\\x=-5\end{array} \right.\)
Vậy `S={7;-5}`