2 câu trả lời
`#huy`
`(x+1)(x^2+x+1)(x-1)(x^2-x+1)`
`=[(x+1)(x^2-x+1)][(x-1)(x^2+x+1)]+1`
`=(x^3+1^3)(x^3-1^3)`
`=x^6-x^3+x^3-1`
`=x^6-1`
`#huy`
`(x+1)(x^2+x+1)(x-1)(x^2-x+1)`
`=[(x+1)(x^2-x+1)][(x-1)(x^2+x+1)]+1`
`=(x^3+1^3)(x^3-1^3)`
`=x^6-x^3+x^3-1`
`=x^6-1`