1 câu trả lời
Đáp án:
Giải thích các bước giải: \[\begin{array}{l} Ta\_co:\\ \frac{1}{{2!}} = \frac{{{2^2} - 3}}{{2!}} = \frac{{{2^2}}}{{2!}} - \frac{3}{{2!}} = \frac{{{2^2}}}{{2!}} - \frac{{{3^2}}}{{3!}}\\ \frac{5}{{3!}} = \frac{{{3^2} - 4}}{{3!}} = \frac{{{3^2}}}{{3!}} - \frac{4}{{3!}} = \frac{{{3^2}}}{{3!}} - \frac{{{4^2}}}{{4!}}\\ ...\\ \frac{{9899}}{{100!}} = \frac{{{{100}^2} - 101}}{{100!}} = \frac{{{{100}^2}}}{{100!}} - \frac{{101}}{{100!}} = \frac{{{{100}^2}}}{{100!}} - \frac{{{{101}^2}}}{{101!}}\\ = > Q = \frac{{{2^2}}}{{2!}} - \frac{{{{101}^2}}}{{101!}} \end{array}\]
