Tính B B= $\frac{\sqrt[]{2 +\sqrt[]{3}}}{2}$ : ($\frac{\sqrt[]{2 +\sqrt[]{3}}}{2}$- $\frac{2}{\sqrt[]{6}}$ +$\frac{\sqrt[]{2+\sqrt[]{3}}}{2\sqrt[]{3}}$ )

Đáp án+Giải thích các bước giải:

 `B = \frac{\sqrt{2 + \sqrt{3}}}{2} : (\frac{\sqrt{2 + \sqrt{3}}}{2} - \frac{2}{\sqrt{6}} + \frac{\sqrt{2 + \sqrt{3}}}{2\sqrt{3}})`

    `= \frac{\sqrt{2 + \sqrt{3}}}{2} : \frac{\sqrt{2 + \sqrt{3}}}{2} - \frac{\sqrt{2 + \sqrt{3}}}{2} : \frac{2}{\sqrt{6}} + \frac{\sqrt{2 + \sqrt{3}}}{2} : \frac{\sqrt{2 + \sqrt{3}}}{2\sqrt{3}}`

   `= \frac{\sqrt{2 + \sqrt{3}}}{2} . \frac{2}{\sqrt{2 + \sqrt{3}}} - \frac{\sqrt{2 + \sqrt{3}}}{2} . \frac{\sqrt{6}}{2} + \frac{\sqrt{2 + \sqrt{3}}}{2} . \frac{2\sqrt{3}}{\sqrt{2 + \sqrt{3}}}`

   `= 1 - \frac{\sqrt{12 + 6\sqrt{3}}}{4} + \sqrt{3}`

   `= 1 - \frac{\sqrt{9 + 2 . 3 .\sqrt{3} + 3}}{4} + \sqrt{3}`

   `= 1 - \frac{(3 + \sqrt{3})²}{4} + \sqrt{3}`

   `= 1 - \frac{3 + \sqrt{3}}{4} + \sqrt{3}`

  `= \frac{4 - 3 - \sqrt{3} + 4\sqrt{3}}{4}`

   `= \frac{1 + 3\sqrt{3}}{4}`