SIN (x+pi/6)= - căn3 /2

Đáp án:

Giải thích các bước giải: sin(x+pi/6)=- √3/2

⇔ $\left \{ {{x+pi/6=-pi/3+k2pi} \atop {x+pi/6=pi+pi/6+k2pi}} \right.$

⇔ $\left \{ {{x=-pi/2+k2pi} \atop {x=7pi/6+k2pi}} \right.$

Ta có: \(\sin (x+\dfrac{\pi}{6})= - {\dfrac{\sqrt{3}}{ 2}}\) \(\Rightarrow \left\{ \begin{array}{l} x+\dfrac{\pi}{6}=-\dfrac{\pi}{3}+k2\pi \\ x+\dfrac{\pi}{6}=\pi+\dfrac{\pi}{3}+k2\pi \end{array} \right .\)\(\Rightarrow \left\{ \begin{array}{l} x=-\dfrac{\pi}{2}+k2\pi \\ x=\dfrac{7\pi}{6}+k2\pi \end{array} \right .\) \((k\in\mathbb Z)\).