Đáp án: Nghiệm của phương trình √3x+√3=√12+√27 - √(3x)+√(3)=√(12)+√(27) ⇔√(3x)+√(3)-√(3)=5√(3)-√(3) ⇔√(3x)=4√(3) ⇔3x=48 ⇔x=16 Vậy nghiệm của phương trình là S = (16)

√(3x)+√(3)=√(12)+√(27) ⇔√(3x)+√(3)-√(3)=5√(3)-√(3) ⇔√(3x)=4√(3) ⇔3x=48 ⇔x=16 Vậy nghiệm của phương trình là S = (16)

√(3x)+√(3)=√(12)+√(27) ⇔√(3x)+√(3)=5√(3) ⇔√(3x)+√(3)-√(3)=5√(3)-√(3) ⇔√(3x)=4√(3) ⇔3x=48 ⇔x=16 (Vậy pt có nghiệm S = (16))

Trúc Linh

4 tháng trước

Nghiệm của phương trình √3x+√3=√12+√27

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trunghieu777

4 tháng trước

$\sqrt{3x}+\sqrt{3}=\sqrt{12}+\sqrt{27}$

$⇔\sqrt{3x}+\sqrt{3}-\sqrt{3}=5\sqrt{3}-\sqrt{3}$

$⇔\sqrt{3x}=4\sqrt{3}$

$⇔3x=48$

$⇔x=16$

Vậy nghiệm của phương trình là `S = {16}`

baonhivu1234

4 tháng trước

$\sqrt{3x}+\sqrt{3}=\sqrt{12}+\sqrt{27}$

$⇔\sqrt{3x}+\sqrt{3}=5\sqrt{3}$

$⇔\sqrt{3x}+\sqrt{3}-\sqrt{3}=5\sqrt{3}-\sqrt{3}$

$⇔\sqrt{3x}=4\sqrt{3}$

$⇔3x=48$

$⇔x=16$

$\text{Vậy pt có nghiệm S = {16}}$

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