Đáp án: m bình - 2m -5=0 tìm m - m^2-2m-5=0 <=>m^2-2m+1-6=0 <=>(m-1)^2=6 <=>∣m-1∣=sqrt(6) <=>[ (l)m-1=√(6)m-1=-√(6) <=>[ (l)m=√(6)+1m=-√(6)+1 Vậy S=(sqrt(6)+1;-sqrt(6)+1)

m^2-2m-5=0 <=>m^2-2m+1-6=0 <=>(m-1)^2=6 <=>∣m-1∣=sqrt(6) <=>[ (l)m-1=√(6)m-1=-√(6) <=>[ (l)m=√(6)+1m=-√(6)+1 Vậy S=(sqrt(6)+1;-sqrt(6)+1)

m^2 - 2m -5=0 ⇔m^2=2m+5 ⇔(m-2)m-5=0 ⇔(m-1)^2-6=0 ⇔(m-1)^2-6+6=0+6 ⇔(m-1)^2=6 ⇔[ (l)m-1=√(6)m-1=-√(6) ⇔[ (l)m=√(6)+1m=-√(6)+1 (Vậy m=√(6)+1 và m=-√(6)+1)

kkieuanh182007

6 tháng trước

m bình - 2m -5=0 . tìm m

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winduc347

6 tháng trước

`m^2-2m-5=0`

`<=>m^2-2m+1-6=0`

`<=>(m-1)^2=6`

`<=>|m-1|=sqrt{6}`

`<=>`$\left[ \begin{array}{l}m-1=\sqrt{6}\\m-1=-\sqrt{6}\end{array} \right.$

`<=>`$\left[ \begin{array}{l}m=\sqrt{6}+1\\m=-\sqrt{6}+1\end{array} \right.$

Vậy `S={sqrt{6}+1;-sqrt{6}+1}.`

baonhivu1234

6 tháng trước

$m^2\:-\:2m\:-5=0$

$⇔m^2=2m+5$

$⇔\left(m-2\right)m-5=0$

$⇔\left(m-1\right)^2-6=0$

$⇔\left(m-1\right)^2-6+6=0+6$

$⇔\left(m-1\right)^2=6$

$⇔\left[ \begin{array}{l}m-1=\sqrt{6}\\m-1=-\sqrt{6}\end{array} \right.$ $⇔\left[ \begin{array}{l}m=\sqrt{6}+1\\m=-\sqrt{6}+1\end{array} \right.$

$\text{Vậy $m=\sqrt{6}+1$ và $m=-\sqrt{6}+1$}$

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