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Thanh Trúc
2 năm trước

Hấp thụ hoàn toàn 8,064 lít SO3 273 độ C, 0,5 atm vào 500ml nước thu được dung dịch A . Tính C% của dung dịch A

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namtran1997
2 năm trước

Ta co $PV = n RT$ voi $R = 0,082$

Vay $n = PV/(RT) = 0,5.8,064/[0,082.(273+273)] = 0,09$ (mol)

$m_{SO_3} = 0,09.80 = 7,2$ (g)

$C\% = \dfrac{0,09.80}{500+0,09.80} .100\% \approx 1,42\%$

buithaihai04
2 năm trước

Đáp án: 1.74%

Giải thích các bước giải: pt:SO3+H2O--->H2SO4

nso3=pv/rt=0.5×8.064/0.082×(273+273)= 0.09 (xấp xỉ)

=>nh2so4=nso3=0.09

=>mh2so4=8.82g

mh2o=D.v=500g(D=1g/cm3)

=>mdd=mso3+mh2o=507.2

=>C%=(8.82/507.2)×100%=1.74%

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