Đáp án: Giải pt √x+√(x+9)=√(x+1)√(x+4) - √x+√x+9=√x+1+√x+4 =>x+2√(x(x+9))+x+9=x+1+√[2]((x+1)(x+4))+x+4 =>2x+9+2√(x^2+9x)=2x+5+2√(x^2+5x+4) =>4+2√(x^2+9x)=2√(x^2+5x+4) =>2(2+√(x^2+9x))=2√(x^2+5x+4) =>4+x^2+9x+4√(x^2+9x)=x^2+5x+4 =>4x+4√(x^2+9x)=0 =>4(x+√(x^2+9x))=0 =>x+√(x^2+9x)=0 =>√x(√x+√(x+9))=0 mà √x+√(x+9)≥ √(9)≥ 3>0 nên √x=0 =>x=0 Vậy...

√x+√x+9=√x+1+√x+4 =>x+2√(x(x+9))+x+9=x+1+√[2]((x+1)(x+4))+x+4 =>2x+9+2√(x^2+9x)=2x+5+2√(x^2+5x+4) =>4+2√(x^2+9x)=2√(x^2+5x+4) =>2(2+√(x^2+9x))=2√(x^2+5x+4) =>4+x^2+9x+4√(x^2+9x)=x^2+5x+4 =>4x+4√(x^2+9x)=0 =>4(x+√(x^2+9x))=0 =>x+√(x^2+9x)=0 =>√x(√x+√(x+9))=0 mà √x+√(x+9)≥ √(9)≥ 3>0 nên √x=0 =>x=0 Vậy...

aaashgf

5 tháng trước

Giải pt $\sqrt{x}+\sqrt{x+9}=\sqrt{x+1}\sqrt{x+4}$

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Fanconananime

5 tháng trước

`\sqrt{x}+\sqrt{x}+9=\sqrt{x}+1+\sqrt{x}+4`

$=>x+2\sqrt{x\left(x+9\right)}+x+9=x+1+\sqrt[2]{\left(x+1\right)\left(x+4\right)}+x+4$

`=>2x+9+2\sqrt{x^2+9x}=2x+5+2\sqrt{x^2+5x+4}`

`=>4+2\sqrt{x^2+9x}=2\sqrt{x^2+5x+4}`

$=>2\left(2+\sqrt{x^2+9x}\right)=2\sqrt{x^2+5x+4}$

`=>4+x^2+9x+4\sqrt{x^2+9x}=x^2+5x+4`

`=>4x+4\sqrt{x^2+9x}=0`

$=>4\left(x+\sqrt{x^2+9x}\right)=0$

`=>x+\sqrt{x^2+9x}=0`

$=>\sqrt{x}\left(\sqrt{x}+\sqrt{x+9}\right)=0$

$mà\:\sqrt{x}+\sqrt{x+9}\ge \sqrt{9}\ge 3>0$

`nên` `\sqrt{x}=0`

`=>x=0`

Vậy phương trình vô nghiệm

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Giải pt $\sqrt{x}+\sqrt{x+9}=\sqrt{x+1}\sqrt{x+4}$

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I think you should buy ___ pack of mineral water instead. And you can also buy _ snacks such as potato crisps, 3 kilos of mandarins, 2 kilos of apples, 3 bunches of bananas, ____ cookies and soft candies.

Choose the best answer.
We should decorate our living room with _ orange banner. We also need ____ ribbons, balloons, party hats and costume.

Choose the best answer.
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