Cu--->CuO--->CuCl2---->Cu(OH)2---->CuO---->Cu---->CuSO4
2 câu trả lời
2Cu + $O_{2}$ -t°> 2CuO
CuO + 2HCl -> $CuCl_{2}$ + $H_{2}O$
$CuCl_{2} + 2NaOH -> $ $Cu(OH)_{2}$ + 2NaCl
$Cu(OH)_{2}$ -> CuO + $H_{2}O$
CuO + $H_{2}$ -t°> Cu + $H_{2}O$
Cu + $H_{2}SO_4$ -> $CuSO_{4}$ + $SO_{2}$ + $H_{2}O$
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