2 câu trả lời
`#huy`
`cos^(2)25^o - cos^(2)35^o + cos^(2)45^o - cos^(2)55^o + cos^(2)65^o`
`=(cos^(2)25^o + cos^(2)65^o)-(cos^(2)35^o + cos^(2)55^o)+cos^(2)45^o`
`=(cos^(2)25^o + sin^(2)25^o)-(cos^(2)35^o + sin^(2)35^o)+((\sqrt{2})/2)^2`
`=1-1+1/2`
`=1/2`
`#tnvt`
`cos^2 25^0-cos^2 35^0+cos^2 45^0-cos^2 55^0+cos^2 65^0`
`=cos^2 25^0-cos^2 35^0+cos^2 45^0- sin^2 (90^0-55^0)+sin^2 (90^0-65^0)`
`=cos^2 25^0-cos^2 35^0 +cos^2 45^0 -sin^2 35^0+sin^2 25^0`
`=(cos^2 25^0+sin^2 25^0)-(cos^2 35^0+sin^2 35^0)+(cos45^0)^2`
`=1-1+(\frac{\sqrt{2}}{2})^2`
`=\frac{2}{4}`
`=1/2`
Ta áp dụng công thức : `sin^2a+cos^2a=1`