cho từ từ đến hết dung dịch chứa 0,48 mol HCL vào dung dịch chứa đồng thời x mol Na2Co3 va 0,2 mol NaHCo3 ,sau khi phản ứng xảy ra hoàn toàn , thu được 4,032 lit khí co2 (đktc) tính giá trị của x

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Đáp án:

Lời giải: nCo2=0,18

nH+=nCO32- +nCO2 => nCO32-=x=0,3

\( H^+ + {CO_3}^{2- } \to {HCO_3}^-\)

x x x

\( H^+ + {HCO_3}^- \to CO_2 + H_2O\)

0,48-x 0,2+x 0,18

Do mol \(CO_2\) < \(NaHCO_3\)=> axit hết

0,48-x=0,18

=> x= 0,3

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