Đáp án: Cho hay nhất x cthln x cảm ơn x 5 sao Giai phương trình √x+√(x+1)=(1/√x) - ĐKx>0 PT⇔ x+√(x(x+1))=1 ⇔ √(x^2+x)=1-x(0<x≤ 1) ⇔ x^2+x=1-2x+x^2 ⇔ 3x=1⇔ x=(1/3)(tm) Vậy S=((1/3))

ĐKx>0 PT⇔ x+√(x(x+1))=1 ⇔ √(x^2+x)=1-x(0<x≤ 1) ⇔ x^2+x=1-2x+x^2 ⇔ 3x=1⇔ x=(1/3)(tm) Vậy S=((1/3))

Đáp án (S = ) ((1/3)) Giải thích các bước giải √x+√(x+1)=(1/√x) ⇔√x√x+√(x+1)√x=(1/√x)√x ⇔(√x)^2+√x√(x+1)=1 ⇔x+√x√(x+1)=1 ⇔x^2+x=1-2x+x^2 ⇔x=1-2x ⇔x+2x=1 ⇔3x=1 ⇔x=(1/3) (Vậy pt có nghiệm S = ) ((1/3))

legendaryst

4 tháng trước

Cho hay nhất x cthln x cảm ơn x 5 sao Giai phương trình :: $\sqrt{x}+\sqrt{x+1}=\dfrac{1}{\sqrt{x}}$

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hoangminhava

4 tháng trước

$ĐK:x>0$

$PT\Leftrightarrow x+\sqrt{x(x+1)}=1$

$\Leftrightarrow \sqrt{x^2+x}=1-x(0<x\le 1)$

$\Leftrightarrow x^2+x=1-2x+x^2$

$\Leftrightarrow 3x=1\Leftrightarrow x=\dfrac{1}{3}(tm)$

Vậy $S=\left\{\dfrac{1}{3}\right\}$

baonhivu1234

4 tháng trước

Đáp án:

$\text{S = }$ $\left\{\dfrac{1}{3}\right\}$

Giải thích các bước giải:

$\sqrt{x}+\sqrt{x+1}=\dfrac{1}{\sqrt{x}}$

$⇔\sqrt{x}\sqrt{x}+\sqrt{x+1}\sqrt{x}=\dfrac{1}{\sqrt{x}}\sqrt{x}$

$⇔\left(\sqrt{x}\right)^2+\sqrt{x}\sqrt{x+1}=1$

$⇔x+\sqrt{x}\sqrt{x+1}=1$

$⇔x^2+x=1-2x+x^2$

$⇔x=1-2x$

$⇔x+2x=1$

$⇔3x=1$

$⇔x=\dfrac{1}{3}$

$\text{Vậy pt có nghiệm S = }$ $\left\{\dfrac{1}{3}\right\}$

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Cho hay nhất x cthln x cảm ơn x 5 sao Giai phương trình :: \(\sqrt{x}+\sqrt{x+1}=\dfrac{1}{\sqrt{x}}\)

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Choose the best answer.I think you should buy _____ pack of mineral water instead. And you can also buy _____ snacks such as potato crisps, 3 kilos of mandarins, 2 kilos of apples, 3 bunches of bananas, ______ cookies and soft candies.

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I think you should buy ___ pack of mineral water instead. And you can also buy _ snacks such as potato crisps, 3 kilos of mandarins, 2 kilos of apples, 3 bunches of bananas, ____ cookies and soft candies.

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We should decorate our living room with _ orange banner. We also need ____ ribbons, balloons, party hats and costume.

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I think that ______ cauliflower is not enough for 3 people. Let’s buy one more.