Câu 1: a)2/3+(2/6)^6:(2/3)^5+5×2022^0 b)(-5/3)×11/13+(-5/3)×2/13 c)27×(-1/3)^3+(1009/2022)^0+(1/3)^2
2 câu trả lời
Đáp án + Giải thích các bước giải:
`a) 2/3 + (2/3)^6 : (2/3)^5 + 5 xx 2022^0`
`= 2/3 + (2/3)^(6 - 5) + 5 . 1`
`= 2/3 + (2/3)^1 + 5`
`= 2/3 + 2/3 + 5`
`= 4/3 + 5`
`= 19/3`
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`b) (-5/3) xx 11/13 + (-5/3) xx 2/13`
`= (-5/3) xx (11/13 + 2/13)`
`= (-5/3) xx 1`
`= -5/3`
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`c) 27 xx (-1/3)^3 + (1009/2022)^0 + (1/3)^2`
`= 27 xx (-1/27) + 1 + 1/9`
`= -1 + 1 + 1/9`
`= 0 + 1/9`
`= 1/9`
a) `2/3 + (2/3)^6 : (2/3)^5 + 5xx2022^0`
`= 2/3 + (2/3)^(6-5) + 5xx1`
`= 2/3 + (2/3)^1 + 5`
`= 2/3 + 2/3 + 5`
`= 4/3 + 15/3`
`= 19/3`
b) `(-5/3) xx 11/13 + (-5/3) xx 2/13`
`= (-5/3) xx (11/13 + 2/13)`
`= (-5/3) xx 13/13`
`= (-5/3)xx1`
`= -5/3`
c) `27xx(-1/3)^3 + (1009/2022)^0+(1/3)^2`
`= 27 xx (-1/27) + 1+ 1/9`
`= -27/27+27/27+1/9`
`= 0+1/9`
`= 1/9`
