căn bậc 3 của x-1=x-1 giá trị x là

$\text{$\sqrt[3]{x}$-1=x-1 }$

$\text{⇔($\sqrt[3]{x}$-1)=$\sqrt[3]{x^{3}}$-1$^{3}$}$

$\text{⇔($\sqrt[3]{x}$-1)=($\sqrt[3]{x}$-1)($\sqrt[3]{x^2}$+$\sqrt[3]{x}$+1)}$

$\text{⇔($\sqrt[3]{x}$-1)-($\sqrt[3]{x}$-1)($\sqrt[3]{x^2}$+$\sqrt[3]{x}$+1)=0}$

$\text{⇔($\sqrt[3]{x}$-1)(1-$\sqrt[3]{x^2}$-$\sqrt[3]{x}$-1)=0}$

$\text{⇔($\sqrt[3]{x}$-1)(-$\sqrt[3]{x^2}$-$\sqrt[3]{x}$)=0}$

$\text{⇔$\left[\begin{matrix} \sqrt[3]{x}-1=0\\ -\sqrt[3]{x^2}-\sqrt[3]{x}=0\end{matrix}\right.$}$

$\text{⇔$\left[\begin{matrix} x=1\\ x^2=-x\end{matrix}\right.$}$

$\text{⇔$\left[\begin{matrix} x=1\\ x=0 \\x=-1\end{matrix}\right.$}$

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