6√12 - √20 - 2√27 + √125

2 câu trả lời

`6\sqrt{12} - \sqrt{20} -2\sqrt{27} + \sqrt{125}`

`=6\sqrt{4.3} - \sqrt{4.5} -2\sqrt{9.3} + \sqrt{25.5}`

`=6\sqrt{2².3} - \sqrt{2².5} -2\sqrt{3².3} + \sqrt{5².5}`

`=6.2\sqrt{3} - 2\sqrt{5} - 2.3\sqrt{3} + 5\sqrt{5}`

`=12\sqrt{3} - 6\sqrt{3} -2\sqrt{5} + 5\sqrt{5}`

`=6\sqrt{3} + 3\sqrt{5}`

6√12 - √20 - 2√27 + √125

= 6.2$\sqrt{3}$ - 2$\sqrt{5}$  - 2.3$\sqrt{3}$ + 5$\sqrt{5}$

= 12 $\sqrt{3}$ - 2$\sqrt{5}$ - 6$\sqrt{3}$ + 5 $\sqrt{5}$

= 6 $\sqrt{3}$ + 3$\sqrt{5}$ 

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