1 câu trả lời
`3x+7√x-6=0`
`3x+9√x-2√x-6=0`
`3√x.(√x+3)-2.(√x+3)=0`
`(√x+3)(3√x-2)=0`
TH1
`√x+3=0`
`√x=-3`
`x=-√3`
TH2
`3√x-2=0`
`3√x=2`
`√x=2/3`
`x=√(2/3)`
Vậy `x∈{-√3 ; √(2/3)}`
Cho mk xin hay nhất please
Thank you
`3x+7√x-6=0`
`3x+9√x-2√x-6=0`
`3√x.(√x+3)-2.(√x+3)=0`
`(√x+3)(3√x-2)=0`
TH1
`√x+3=0`
`√x=-3`
`x=-√3`
TH2
`3√x-2=0`
`3√x=2`
`√x=2/3`
`x=√(2/3)`
Vậy `x∈{-√3 ; √(2/3)}`
Cho mk xin hay nhất please
Thank you