Đáp án: √((√3 −1)^2 ) − √4+2√3 - Đáp án -2 Giải thích các bước giải √((√(3)-1)^2)-√( 4+2√(3)) =∣√(3)-1∣-√(3+2√(3)+1) =(√(3)-1)-√((√(3)+1)^2) =√(3)-1-∣√(3)+1∣ =√(3)-1-(√(3)+1) =√(3)-1-√(3)-1 =(√(3)-√(3))+(-1-1) =0+(-2) =-2

Đáp án -2 Giải thích các bước giải √((√(3)-1)^2)-√( 4+2√(3)) =∣√(3)-1∣-√(3+2√(3)+1) =(√(3)-1)-√((√(3)+1)^2) =√(3)-1-∣√(3)+1∣ =√(3)-1-(√(3)+1) =√(3)-1-√(3)-1 =(√(3)-√(3))+(-1-1) =0+(-2) =-2

Đáp án + Giải thích các bước giải √((√(3)-1)^2)-√(4+2√(3)) = ∣√(3)-1∣ - √(3+2√(3)+1) = ∣√(3)-1∣ - √((√(3))^2+2√(31)+1^2) = √(3)-1 - √((√(3)+1)^2) = √(3)-1-∣√(3)+1∣ = √(3)-1-√(3)-1 = -2

linhcutechuacony

5 tháng trước

√((√3 −1)^2 ) − √4+2√3

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Doraemon19

5 tháng trước

Đáp án:

`-2`

Giải thích các bước giải:

`\sqrt{(\sqrt{3}-1)^2}-\sqrt{ 4+2\sqrt{3}}`

`=|\sqrt{3}-1|-\sqrt{3+2\sqrt{3}+1}`

`=(\sqrt{3}-1)-\sqrt{(\sqrt{3}+1)^2}`

`=\sqrt{3}-1-|\sqrt{3}+1|`

`=\sqrt{3}-1-(\sqrt{3}+1)`

`=\sqrt{3}-1-\sqrt{3}-1`

`=(\sqrt{3}-\sqrt{3})+(-1-1)`

`=0+(-2)`

`=-2`

pchi0802

5 tháng trước

Đáp án + Giải thích các bước giải:

`\sqrt{(\sqrt{3}-1)^2}-\sqrt{4+2\sqrt{3}}`

`= |\sqrt{3}-1| - \sqrt{3+2\sqrt{3}+1}`

`= |\sqrt{3}-1| - \sqrt{(\sqrt{3})^2+2\sqrt{3.1}+1^2}`

`= \sqrt{3}-1 - \sqrt{(\sqrt{3}+1)^2}`

`= \sqrt{3}-1-|\sqrt{3}+1|`

`= \sqrt{3}-1-\sqrt{3}-1`

`= -2`

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