1 câu trả lời
$2cos(\frac{3x}{2}-10^o)+\sqrt3=0 \\ \\ \Leftrightarrow cos(\frac{3x}{2}-10^o)=\frac{-\sqrt3}{2} \\ \\ \Leftrightarrow \left\{\begin{matrix} \frac{3x}{2}-10^o=150^o+k360^0 & \\ \\ \frac{3x}{2}-10^o=-150^o+k360^0& \end{matrix}\right. \\ \\ \\ \Leftrightarrow \left\{\begin{matrix} x=\frac{320}{3}^o+k240^o & \\ \\ x=\frac{-280}{3}^o+k240^o & \end{matrix}\right.$
Câu hỏi trong lớp
Xem thêm
