1 câu trả lời
$\left(\sqrt{2}-y\sqrt{3}\right)\sqrt{2}-y\sqrt{3}=1$
$⇒2-\sqrt{6}y-\sqrt{3}y=1$
$⇒2-\sqrt{6}y-\sqrt{3}y-2=1-2$
$⇒-\sqrt{6}y-\sqrt{3}y=-1$
$⇒-\left(\sqrt{6}+\sqrt{3}\right)y=-1$
$⇒\dfrac{-\left(\sqrt{6}+\sqrt{3}\right)y}{-\sqrt{6}-\sqrt{3}}=\dfrac{-1}{-\sqrt{6}-\sqrt{3}}$
$⇒y=\dfrac{\sqrt{6}-\sqrt{3}}{3}$