(2 - √3)^x + (2- √3)^x = (√5)^x . Tìm x

2 câu trả lời

`\text{~~Holi~~}`

`(2-\sqrt{3})^x+(2-\sqrt{3})^x=(\sqrt{5})^x`

`-> 2(2-\sqrt{3})^x=\sqrt{5}^x`

`-> 2((2-\sqrt{3})/(\sqrt{5}))^x=1`

`-> ((2-\sqrt{3})/(\sqrt{5}))^x=1/2`

`-> x=-log_{(2\sqrt{5}-\sqrt{15})/5} (2)`

`(2 - sqrt{3})^{x} + (2 - sqrt{3})^{x} = (sqrt{5})^{x}`

`-> 2(2 - sqrt{3})^{x} = (sqrt{5})^{x}`

`-> ((2 - \sqrt{3})/(\sqrt{5}))^{x} = 1/2`

`->` $x = log_{\dfrac{2 - \sqrt{3}}{\sqrt{5}}} \dfrac{1}{2}$

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