2 câu trả lời
\(x-5+x-5+x-5=15\)
\(\left(x-5\right)\times3=15\)
\(x-5=15\div3\)
\(x-5=5\)
\(x=5+5\)
\(x=10\)
Ta có: x-5+x-5+x-5=15
=>(x-5).3=15
=>x-5=15:3
=>x-5=5
=>x=5+5
=>x=10
\(x-5+x-5+x-5=15\)
\(\left(x-5\right)\times3=15\)
\(x-5=15\div3\)
\(x-5=5\)
\(x=5+5\)
\(x=10\)
Ta có: x-5+x-5+x-5=15
=>(x-5).3=15
=>x-5=15:3
=>x-5=5
=>x=5+5
=>x=10
