Đáp án: x+2/338 + x+3/337 + x + 4/336 + x+5/335 + x + 360/5 =0 (tìm x) - gửi tus ak (x+2/338/+) (x+3/337/+) (x+4/336/+) (x+5/335/+) (x+360/5/=0) (x+2/338/+ 1) (x+3/337/+1) (x+4/336/+1) (x+5/335/+1) (x+360/5 )-4 (=0) (x+340/338/+) (x+340/337/+) (x+340/336/+) (x+340/335/+) (x+340/5/=0) ((x+340))((1/338/+) (1/337/+) (1/336/+) (1/335/+) (1/5))(= 0) Vì ((1/338/+) (1/337/+) (1...

gửi tus ak (x+2/338/+) (x+3/337/+) (x+4/336/+) (x+5/335/+) (x+360/5/=0) (x+2/338/+ 1) (x+3/337/+1) (x+4/336/+1) (x+5/335/+1) (x+360/5 )-4 (=0) (x+340/338/+) (x+340/337/+) (x+340/336/+) (x+340/335/+) (x+340/5/=0) ((x+340))((1/338/+) (1/337/+) (1/336/+) (1/335/+) (1/5))(= 0) Vì ((1/338/+) (1/337/+) (1...

Ginarmy

5 tháng trước

x+2/338 + x+3/337 + x + 4/336 + x+5/335 + x + 360/5 =0 (tìm x)

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5 tháng trước

gửi tus ak

$\dfrac{x+2}{338}$ $\text{+}$ $\dfrac{x+3}{337}$ $\text{+}$ $\dfrac{x+4}{336}$ $\text{+}$ $\dfrac{x+5}{335}$ $\text{+}$ $\dfrac{x+360}{5}$ $\text{=0}$

$\dfrac{x+2}{338}$ $\text{+ 1}$ $\dfrac{x+3}{337}$ $\text{+1}$ $\dfrac{x+4}{336}$ $\text{+1}$ $\dfrac{x+5}{335}$ $\text{+1}$ $\dfrac{x+360}{5 }-4$ $\text{=0}$

$\dfrac{x+340}{338}$ $\text{+}$ $\dfrac{x+340}{337}$ $\text{+}$ $\dfrac{x+340}{336}$ $\text{+}$ $\dfrac{x+340}{335}$ $\text{+}$ $\dfrac{x+340}{5}$ $\text{=0}$

$\text{(x+340)}$ ( $\dfrac{1}{338}$ $\text{+}$ $\dfrac{1}{337}$ $\text{+}$ $\dfrac{1}{336}$ $\text{+}$ $\dfrac{1}{335}$ $\text{+}$ $\dfrac{1}{5}$ ) $\text{= 0}$

Vì ( $\dfrac{1}{338}$ $\text{+}$ $\dfrac{1}{337}$ $\text{+}$ $\dfrac{1}{336}$ $\text{+}$ $\dfrac{1}{335}$ $\text{+}$ $\dfrac{1}{5}$ ) luôn > $\text{> 0}$ nên