x+2/338 + x+3/337 + x + 4/336 + x+5/335 + x + 360/5 =0 (tìm x)

gửi tus ak

$\dfrac{x+2}{338}$$\text{+}$ $\dfrac{x+3}{337}$$\text{+}$ $\dfrac{x+4}{336}$$\text{+}$ $\dfrac{x+5}{335}$$\text{+}$ $\dfrac{x+360}{5}$$\text{=0}$ 

$\dfrac{x+2}{338}$$\text{+ 1}$ $\dfrac{x+3}{337}$$\text{+1}$ $\dfrac{x+4}{336}$$\text{+1}$ $\dfrac{x+5}{335}$$\text{+1}$ $\dfrac{x+360}{5 }-4$$\text{=0}$

$\dfrac{x+340}{338}$$\text{+}$ $\dfrac{x+340}{337}$$\text{+}$ $\dfrac{x+340}{336}$$\text{+}$ $\dfrac{x+340}{335}$$\text{+}$ $\dfrac{x+340}{5}$$\text{=0}$

$\text{(x+340)}$($\dfrac{1}{338}$$\text{+}$ $\dfrac{1}{337}$$\text{+}$ $\dfrac{1}{336}$$\text{+}$ $\dfrac{1}{335}$$\text{+}$ $\dfrac{1}{5}$)$\text{= 0}$

Vì ($\dfrac{1}{338}$$\text{+}$ $\dfrac{1}{337}$$\text{+}$ $\dfrac{1}{336}$$\text{+}$ $\dfrac{1}{335}$$\text{+}$ $\dfrac{1}{5}$) luôn >$\text{> 0}$ nên 

⇒ $\text{x+340=0}$

⇒ $\text{x=-340}$