x+2/338 + x+3/337 + x + 4/336 + x+5/335 + x + 360/5 =0 (tìm x)
2 câu trả lời
gửi tus ak
$\dfrac{x+2}{338}$$\text{+}$ $\dfrac{x+3}{337}$$\text{+}$ $\dfrac{x+4}{336}$$\text{+}$ $\dfrac{x+5}{335}$$\text{+}$ $\dfrac{x+360}{5}$$\text{=0}$
$\dfrac{x+2}{338}$$\text{+ 1}$ $\dfrac{x+3}{337}$$\text{+1}$ $\dfrac{x+4}{336}$$\text{+1}$ $\dfrac{x+5}{335}$$\text{+1}$ $\dfrac{x+360}{5 }-4 $$\text{=0}$
$\dfrac{x+340}{338}$$\text{+}$ $\dfrac{x+340}{337}$$\text{+}$ $\dfrac{x+340}{336}$$\text{+}$ $\dfrac{x+340}{335}$$\text{+}$ $\dfrac{x+340}{5}$$\text{=0}$
$\text{(x+340)}$($\dfrac{1}{338}$$\text{+}$ $\dfrac{1}{337}$$\text{+}$ $\dfrac{1}{336}$$\text{+}$ $\dfrac{1}{335}$$\text{+}$ $\dfrac{1}{5}$)$\text{= 0}$
Vì ($\dfrac{1}{338}$$\text{+}$ $\dfrac{1}{337}$$\text{+}$ $\dfrac{1}{336}$$\text{+}$ $\dfrac{1}{335}$$\text{+}$ $\dfrac{1}{5}$) luôn >$\text{> 0}$ nên
⇒ $\text{x+340=0}$
⇒ $\text{x=-340}$
` Huy `
` (x+2)/338 + (x+3)/337 + (x+4)/336 + (x+5)/335 + (x+360)/5 =0 `
` => ( (x+2)/338 + 1 ) + ( (x+3)/337 + 1 ) + ( (x+4)/336 + 1 ) + ( (x+5)/335 + 1 ) + ( (x+360)/5 - 4 ) = 0 `
` => ( (x+2)/338 + 338/338 ) + ( (x+3)/337 + 337/337 ) + ( (x+4)/336 + 336/336 ) + ( (x+5)/335 + 335/335 ) + ( (x+360)/5 - 20/20 ) = 0 `
` => (x+340)/338 + (x+340)/337 + (x+340)/336 + (x+340)/335 + (x+340)/5 = 0 `
` => (x+340)(1/338 + 1/337 + 1/336 + 1/335 + 1/5 ) = 0 `
` => x+340=0 `
` => x=-340 `
