Trung hòa 50ml dung dịch HCl 2M= dung dịch Ca(OH)² a viết pt b tính m muối tạo thành c tính m Ca(OH)² phản ứng d nếu trung hòa lượng axit trên với 200g dung dịch NaOH thì khối lượng muối tạo thành là bao nhiêu

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Bạn tham khảo!

$\text{a) Ta có PTHH sau:}$

$\text{2HCl+Ca(OH)2$\rightarrow$CaCl2+H2O}$

$\text{Số mol của HCl là:}$
$\text{n=CM.V=2.0,05=0,1 mol}$

$\rightarrow$ $\text{nCaCl2=0,05 mol}$

$\text{b) mCaCl2=0,05.111=5,55g}$

$\text{c) Có nCa(OH)2=nCaCl2=0,05 mol}$

$\rightarrow$ $\text{mCa(OH)2=n.M=0,05.74=3,7g}$

$\text{Có PTHH tiếp theo:}$

$\text{HCl+NaOH$\rightarrow$NaCl+H2O}$

$\text{Có nNaCl=nHCl=0,1 mol}$

$\rightarrow$ $\text{d) mNaCl=n.M=0,1.75,5=7,55g}$

#TRANPHAMGIABAO

 

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