trộn 150g dd ba(oh)2 17,1% vs 200g ddHCl 7,3%.DD thu đc sau Pu đổi màu ntn?trộn 150g dd ba(oh)2 17,1% vs 200g ddHCl 7,3%.DD thu đc sau Pu đổi màu ntn?

1 câu trả lời

C% Ba(OH)2 = $\frac{mct}{mdd}$ . 100

=> 17,1 = $\frac{n.M}{150}$ . 100 = $\frac{n.171}{150}$ . 100

=> $n_{Ba(OH)2}$ = 0,15 (mol)

C% HCl = $\frac{mct}{mdd}$ . 100

=> 7,3 = $\frac{n.M}{200}$ . 100 = $\frac{n.36,5}{200}$ . 100

=> $n_{HCl}$ = 0,4 (mol)

PT: Ba(OH)2 + 2HCl ---> BaCl2 + 2H2O

Lập tỉ lệ: $\frac{n_{Ba(OH)2}}{1}$ (=$\frac{0,15}{1}$) < $\frac{n_{HCl}}{2}$ (=$\frac{0,4}{2}$) 

-> Ba(OH)2 hết, HCl dư.

Vì HCl dư nên sau PƯ, dung dịch thu được làm quỳ tím chuyển sang màu đỏ (vì HCl là axit).

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