Tính giá trị của biểu thức M = 2x^2 + 3y^2 -5xy + 1 tại x=-2 và y = 1/2.

2 câu trả lời

Đáp án:

Thay x=-2;y=12 vào biểu thức, ta có :

M=2.(-2)2+3.(12)2-5.(-2).12+1

=2.4+3.14+5.1+1

=8+34+5+1

=354+6

=594

Vậy M=594 khi x=-2;y=12.

Thay x=-2y=12 vào biểu thức M ta được:

M=2.(-2)2+3.(12)2-5.(-2).(12)+1

M=2.4+3.14-(-5)+1

M=8+34+6

M=354+6

M=594

 

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