tìm x.y biết |x-9|+3x+2=6

2 câu trả lời

$\textit{Đáp án + Giải thích các bước giải:}$

`|x-9|+3x+2=6`

`=>|x-9|=6-3x-2`

`=>x-9=+-(4-3x)`

$TH1:$ `x \ge 9`

`=>x-9=4-3x`

`=>x+3x=4+9`

`=>4x=13`

`=>x=13/4` $(ktm)$

$TH2:$ `x<9`

`=>x-9=-(4-3x)`

`=>x-9=-4+3x`

`=>x-3x=-4+9`

`=>-2x=5`

`=>x=-5/2` $(tm)$

Vậy `x=-5/2`

 

#andy

\[\begin{array}{l}
\left| {x - 9} \right| + 3x + 2 = 6\left( {DKXD:x \ge 9} \right)\\
 \Leftrightarrow \left| {x - 9} \right| + 3x = 4\\
 \Leftrightarrow \left| {x - 9} \right| = 4 - 3x\\
 \Leftrightarrow \left[ \begin{array}{l}
x - 9 = 4 - 3x\\
x - 9 =  - 4 + 3x
\end{array} \right.\\
 \Leftrightarrow \left[ \begin{array}{l}
x + 3x = 4 + 9\\
x - 3x =  - 4 + 9
\end{array} \right.\\
 \Leftrightarrow \left[ \begin{array}{l}
4x = 13\\
 - 2x = 5
\end{array} \right.\\
 \Leftrightarrow \left[ \begin{array}{l}
x = \dfrac{{13}}{4}\left( {TMDK} \right)\\
x =  - \dfrac{5}{2}\left( {KTMDK} \right)
\end{array} \right.\\
 \Rightarrow S = \left\{ {\dfrac{{13}}{4}} \right\}
\end{array}\]