1 câu trả lời
√x−1√x :(√x−1√x+1 +1−√xx+√x )
=√x−1√x :((√x−1)√x(√x+1)√x +1−√xx+√x )
=√x−1√x :(x−√xx+√x +1−√xx+√x )
=√x−1√x :x−2√x+1x+√x
=√x−1√x :(√x−1)2√x(√x+1)
=√x−1√x .√x(√x+1)(√x−1)2
=√x+1√x−1
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