mn ơi giúp mik vs ạ,mik đang cần gấp:Hoàn thành dãy chuyển hóa sau Al-->Al2(SO4)3-->AlCL3-->Al(OH)3-->Al2O3-->Al2(CO3)3-->Al-->Al2O3

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Đề)

$\text{Al$\xrightarrow{1}$Al2(SO4)3$\xrightarrow{2}$AlCl3$\xrightarrow{3}$Al(OH)3$\xrightarrow{4}$Al2O3$\xrightarrow{5}$Al2(CO3)3$\xrightarrow{6}$Al$\xrightarrow{7}$Al2O3}$

Bài làm)

$1)$ $2Al$ $+$ $3H_2(SO_4)_3$ $\rightarrow$ $Al_2(SO_4)_3$ $+$ $3H_2$

$2)$ $Al_2(SO_4)_3$ $+$ $3BaCl_2$ $\rightarrow$ $3BaSO_4$ $+$ $2AlCl_3$

$3)$ $AlCl_3$ $+$ $3NaOH$ $\rightarrow$ $3NaCl$ $+$ $Al(OH)_3$ 

$4)$ $2Al(OH)_3$ $\xrightarrow{t^o}$ $Al_2O_3$ $+$ $3H_2O$

$5)$ $Al_2O_3$ $+$ $3H_2CO_3$ $\rightarrow$ $Al_2(CO_3)_3$ $+$ $3H_2O$

$6)$ $Al_2(CO_3)_3$ $+$ $3Mg$ $\rightarrow$ $3MgCO_3$ $+$ 2$Al$

$7)$ $4Al$ $+$ $3O_2$ $\xrightarrow{t^o}$ $2Al_2O_3$

 

- `2Al``+``3H_2``SO_4``→``Al_2(SO_4)_3``+``3H_2`

- `Al_2(SO_4)_3``+``3BaCl_2``→``3BaSO_4↓``+``2AlCl_3`

- `AlCl_3``+``3NaOH``→``Al(OH)_3``+``3NaCl`

- `2Al(OH)_3` $\xrightarrow[]{t^o}$ `Al_2``O_3``+``3H_2O`

- `Al_2``O_3``+``3CO_2``→``Al_2(CO_3)_3`

- `3Mg``+``Al_2(CO_3)_3` $\xrightarrow[]{t^o}$ `3MgCO_3``+``2Al`

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