Hòa tan hoàn toàn 8 gam đồng (II) oxit CuO cần dùng 200 gam dung dịch HCl thu được dung dịch X. a) Tính khối lượng muối thu được trong dung dịch X. b) Tính nồng độ phần trăm dung dịch HCl phản ứng. c) Tính nồng độ phần trăm của muối trong dung dịch X.

2 câu trả lời

 

Em tham khảo nha :

\(\begin{array}{l}
a)\\
CuO + 2HCl \to CuC{l_2} + {H_2}O\\
{n_{CuO}} = \dfrac{8}{{80}} = 0,1mol\\
{n_{CuC{l_2}}} = {n_{CuO}} = 0,1mol\\
{m_{CuC{l_2}}} = 0,1 \times 135 = 13,5g\\
b)\\
{n_{HCl}} = 2{n_{CuO}} = 0,2mol\\
{m_{HCl}} = 0,2 \times 36,5 = 7,3g\\
C{\% _{HCl}} = \dfrac{{7,3}}{{200}} \times 100\%  = 3,65\% \\
c)\\
C{\% _{CuC{l_2}}} = \dfrac{{13,5}}{{8 + 200}} \times 100\%  = 6,5\% 
\end{array}\)

 

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