hòa tan hoàn toàn 32 gam CuO vào 200 gam dung dịch H2SO4 tính nồng độ phần trăm của dung dịch thu được

2 câu trả lời

Bạn tham khảo!

Đáp án:

 $\text{C%CuSO4=28,5%}$

Giải thích các bước giải:

 $\text{Ta có PTHH sau:}$

$\text{CuO+H2SO4$\rightarrow$CuSO4+H2O}$

$\text{Số mol của CuO là:}$

$\text{n=$\frac{m}{M}$=$\frac{32}{80}$=0,4 mol}$

$\text{Có nCuSO4=nCuO=0,4 mol}$

$\rightarrow$ $\text{mCuSO4=0,4.160=64g}$

$\text{Có mH2O=n.M=0,4.18=7,2g}$

$\rightarrow$ $\text{mdd CuSO4=32+200-7,2=224,8g}$

$\text{C% CuSO4=$\frac{mct}{mdd}$.100=$\frac{64}{224,8}$.100=28,5%}$

#TRANPHAMGIABAO

Em tham khảo nha :

\(\begin{array}{l}
CuO + {H_2}S{O_4} \to CuS{O_4} + {H_2}O\\
{n_{CuO}} = \dfrac{{32}}{{80}} = 0,4mol\\
{n_{CuS{O_4}}} = {n_{CuO}} = 0,4mol\\
{m_{CuS{O_4}}} = 0,4 \times 160 = 64g\\
C{\% _{CuS{O_4}}} = \dfrac{{64}}{{32 + 200}} \times 100\%  = 27,6\% 
\end{array}\)

 

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