Hòa tan hết 5,6 gam CaO vào dung dịch HCl 14,6%. Khối lượng dung dịch HCl đã dùng là

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nCaO = 0,1 mol

CaO    + 2HCl → CaCl2 + H2O

0,1 mol → 0,2 mol

⇒ mHCl = 0,2 × 36,5 = 7,3 gam

⇒ Khối lượng dung dịch HCl đã dùng là:

mHCl = $\frac{7,3 × 100 phantram }{14,6 phantram }$ = 50 (gam)

 

 

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