Đáp án: Dẫn 11,2 lít khí CO2 vào dung dịch NAOHdư Tính khối lượng muối sinh ra ( khí đó thuộc điều kiện tiêu chuẩn) - Đáp án Giải thích các bước giải CO_2 + 2NaOH → Na_2CO_3 + H_2O n_(CO_2) = (11,2/22,4) = 0,5 mol n_(Na_2CO_3) = n_(CO_2) = 0,5 mol m_(Na_2CO_3) = 0,5 106 = 53g Chúc bạn học tốt #aura

Đáp án Giải thích các bước giải CO_2 + 2NaOH → Na_2CO_3 + H_2O n_(CO_2) = (11,2/22,4) = 0,5 mol n_(Na_2CO_3) = n_(CO_2) = 0,5 mol m_(Na_2CO_3) = 0,5 106 = 53g Chúc bạn học tốt #aura

n_(CO_2) = V/(22,4) = (11,2)/(22,4) = 0,5mol PTHH CO_2 + 2NaOH →(t^o) Na_2CO_3 + H_2O 1 2 1 1 (mol) 0,5 1 0,5 0,5 (mol) m_(Na_2CO_3) = nM = 0,5106 = 53g

nhuquynh3001

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Dẫn 11,2 lít khí CO2 vào dung dịch NAOHdư. Tính khối lượng muối sinh ra ( khí đó thuộc điều kiện tiêu chuẩn)

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Aura Aura

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Đáp án:

Giải thích các bước giải:

`CO_2 + 2NaOH → Na_2CO_3 + H_2O`

`n_{CO_2}` = $\frac{11,2}{22,4}$ = 0,5 mol

`n_{Na_2CO_3}` = `n_{CO_2}` = 0,5 mol

`m_{Na_2CO_3}` = 0,5 . 106 = 53g

Chúc bạn học tốt #aura

MuaCute

2 tháng trước

`n_{CO_2} = V/{22,4} = {11,2}/{22,4} = 0,5mol`

`PTHH : CO_2 + 2NaOH` $\xrightarrow[]{t^o}$ `Na_2CO_3 + H_2O`

`1` : `2` : `1` : `1` `(mol)`

`0,5` `1` `0,5` `0,5` `(mol)`

`m_{Na_2CO_3} = n.M = 0,5.106 = 53g`

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Dẫn 11,2 lít khí CO2 vào dung dịch NAOHdư. Tính khối lượng muối sinh ra ( khí đó thuộc điều kiện tiêu chuẩn)

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