PTHH
`NaOH+ HCl -> NaCl+ H_2O `
`n_(NaOH)=(20)/(40)=0,5(mol)`
PTHH:
NaOH + HCL -> NaCl + H2O
nNaOH = $\frac{20}{40}$ = 0.5 (mol)
Choose the best answer.
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