a) A= $6 + 3^2 .2 -6.3^2/ 3^2+3.3^2-3^4$ b) B= $2^{12}$ . $3^5-4^6.9^2/ (2^2.3)^6+8^4.3^5$ giúp với !!! nhanh nhất cho trlhn
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Đáp án:
$A=\dfrac{6+3^2.2-6.3^2}{3^2+3.3^2-3^4}\\\Rightarrow A=\dfrac{2.3+3^2.2-2.3.3^2}{3^2+3^3-3^4}\\\Rightarrow A=\dfrac{2.3.(1+3-3^2)}{3^2.\!(1+3-3^2)}\\\Rightarrow A=\dfrac{2.3}{3^2}\\\Rightarrow A=\dfrac23\\B=\dfrac{2^{12}.3^5-4^6.9^2}{\left(2^2.3\right)^6+8^4.3^5}\\\Rightarrow B=\dfrac{2^{12}.3^5-\left(2^2\right)^6.\!\left(3^2\right)^2}{2^{12}.3^6+\left(2^3\right)^4.3^5}\\\Rightarrow B=\dfrac{2^{12}.3^5-2^{12}.3^4}{2^{12}.3^6+2^{12}.3^5}\\\Rightarrow B=\dfrac{2^{12}.3^4.(3-1)}{2^{12}.3^4.\!\left(3^2+3\right)}\\\Rightarrow B=\dfrac{3-1}{3^2+3}\\\Rightarrow B=\dfrac16$
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