(√27 -3√2 + 2√6) : 3√3

Đáp án+Giải thích các bước giải:

`(\sqrt{27}-3\sqrt{2}+2\sqrt{6}):3\sqrt{3}`

`=(\sqrt{9.3}-3\sqrt{2}+2\sqrt{6}).\frac{1}{3\sqrt{3}}`

`=(3\sqrt{3}-3\sqrt{2}+2\sqrt{6}).\frac{1}{3\sqrt{3}}`

`=\frac{3\sqrt{3}}{3\sqrt{3}}-\frac{3\sqrt{2}}{3\sqrt{3}}+\frac{2\sqrt{6}}{3\sqrt{3}}`

`=1-\frac{\sqrt{2}.\sqrt{3}}{\sqrt{3}.\sqrt{3}}+\frac{2.\sqrt{2}}{3}`

`=\frac{3}{3}-\frac{\sqrt{6}}{3}+\frac{2\sqrt{2}}{3}`

`=\frac{3-\sqrt{6}+2\sqrt{2}}{3}`

Đáp án:

`(\sqrt{27}-3\sqrt{2}+2\sqrt{6}):3\sqrt{3}=(3+2\sqrt{2}-\sqrt{6})/3`

Giải thích các bước giải:

` (\sqrt{27}-3\sqrt{2}+2\sqrt{6}):3\sqrt{3}`

`=\sqrt{27}: 3\sqrt{3} -3\sqrt{2}:3\sqrt{3} +2\sqrt{6}:3\sqrt{3}`

`=\sqrt{3^2 .3} : 3\sqrt{3} -(\sqrt{6})/3 + (2\sqrt{2})/3`

`=3\sqrt{3}:3\sqrt{3} + (2\sqrt{2}-\sqrt{6})/3`

`=1+ (2\sqrt{2}-\sqrt{6})/3`

`=3/3 + (2\sqrt{2}-\sqrt{6})/3`

`=(3+2\sqrt{2}-\sqrt{6})/3`

Vậy  `(\sqrt{27}-3\sqrt{2}+2\sqrt{6}):3\sqrt{3}=(3+2\sqrt{2}-\sqrt{6})/3`