2 câu trả lời
Đề
$\Rightarrow\dfrac{1}{x}-\dfrac{1}{x+1}+\dfrac{1}{x+1}-\dfrac{1}{x+2}+\dfrac{1}{x+2}-\dfrac{1}{x+3}-\dfrac{1}{x}=\dfrac{1}{2010}$
$\Rightarrow\dfrac{-1}{x+3}=\dfrac{1}{2010}$
`=>x+3={2010.(-1)}/1`
`=>x+3=-2010`
`=>x=-2010-3`
`=>x=-2013`
