$x^4-x^3-3x-x^4=0$ Tìm x

2 câu trả lời

Answer

`x^4 - x^3 - 3x - x^4 = 0`

`=> (x^4 - x^4) - x^3 - 3x = 0`

`=> -x^3 - 3x = 0`

`=> - (x^3 + 3x) = 0`

`=> -x . (x^2 + 3) = 0`

`=>` $\left[\begin{matrix} -x = 0\\ x^2 + 3 = 0\end{matrix}\right.$

`=>` $\left[\begin{matrix} x = 0\\ x^2 = 0 - 3\end{matrix}\right.$

`=>` $\left[\begin{matrix} x = 0\\ x^2 = -3 \ \text{(Vô lý)}\end{matrix}\right.$

Vậy `x = 0`

$\text{$x^{4}$ - $x^{3}$ - $3x^{}$ - $x^{4}$ = 0}$

⇔ $\text{( $x^{4}$ - $x^{4}$ ) - $x^{3}$ - $3x^{}$ = 0}$ 

⇔ $\text{$-x^{3}$ - $3x^{}$ = 0}$ 

⇔ $\text{$-x^{}$ . ( $x^{2}$ + 3 ) = 0}$ 

⇔ $\left[\begin{matrix} -x=0\\ x^{2} + 3 = 0\end{matrix}\right.$ 

⇔ $\left[\begin{matrix}x=0\\ x^{2} = -3 ( Vô lý )\end{matrix}\right.$

                $\text{Vậy $x^{}$ = 0}$