(x+1/2021)+(x+2/2020)+(x+3/2019)=-3

1 câu trả lời

Đáp án:

Giải thích các bước giải:

$frac{x+1}{2021}+frac{x+2}{2020}+frac{x+3}{2019}=-3$

↔$(\frac{x+1}{2021}+1)+(\frac{x+2}{2020}+1)+(\frac{x+3}{2019}+1)=0$

↔$\frac{x+2022}{2021}+\frac{x+2022}{2020}+\frac{x+2022}{2019}=0$

↔$(x+2022).(\frac{1}{2021}+\frac{1}{2020}+\frac{1}{2019}=0$

↔$x+2022=0$ ↔$x=-2022$