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Đáp án:
$\left[\begin{array}{l} x=-\dfrac{5}{3} \\ x=-\dfrac{1}{9}\end{array} \right..$
Giải thích các bước giải:
$\left|\dfrac{x}{2}-\dfrac{1}{3}\right|=\left|x+\dfrac{1}{2}\right|\\ \left[\begin{array}{l} \dfrac{x}{2}-\dfrac{1}{3}=x+\dfrac{1}{2} \\ \dfrac{x}{2}-\dfrac{1}{3}=-x-\dfrac{1}{2}\end{array} \right.\\ \left[\begin{array}{l} \dfrac{x}{2}-x=\dfrac{1}{3}+\dfrac{1}{2} \\ \dfrac{x}{2}+x=\dfrac{1}{3}-\dfrac{1}{2}\end{array} \right.\\ \left[\begin{array}{l} -\dfrac{x}{2}=\dfrac{5}{6} \\ \dfrac{3x}{2}=-\dfrac{1}{6}\end{array} \right.\\ \left[\begin{array}{l} x=-\dfrac{5}{3} \\ x=-\dfrac{1}{9}\end{array} \right..$
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