tìm x biết -3/4:x/6^2=(1,5)^3.8 =

Đáp án:

Giải thích các bước giải: \[\begin{array}{l} - \frac{3}{4}:\frac{x}{{{6^2}}} = 1,{5^3}.8\\ \Leftrightarrow - \frac{3}{4}:\frac{x}{{36}} = \frac{{27}}{8} \cdot 8\\ \Leftrightarrow - \frac{3}{4}:\frac{x}{{36}} = 27\\ \Leftrightarrow \frac{x}{{36}} = - \frac{3}{4}:27\\ \Leftrightarrow \frac{x}{{36}} = - \frac{1}{{36}}\\ \Leftrightarrow x = - 1 \end{array}\]

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- \frac{3}{4}:\frac{x}{{{6^2}}} = 1,{5^3}.8\left( {x \ne 0} \right)\\

\Leftrightarrow - \frac{3}{4}.\frac{{{6^2}}}{x} = {\left( {\frac{3}{2}} \right)^3}.8\\

\Leftrightarrow - \frac{3}{4}.\frac{{36}}{x} = \frac{{27}}{8}.8\\

\Leftrightarrow - 3.\frac{9}{x} = 27\\

\Leftrightarrow - \frac{{27}}{x} = 27\\

\Leftrightarrow - 27 = 27x\\

\Leftrightarrow x = - 1\left( {Thoa\_man} \right)

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