2 câu trả lời
x+ 3/3 = x-1/2
=> x+ 1/ 1 = x-1/2
=> (x+1)2 =(x-1)1
=> 2x+ 2= x-1
=>2x-x = -3
=> x= -3
`x+ 3/3 = x-1/2`
`=> x+ 1/ 1 = x-1/2`
`=> (x+1)2 =(x-1)1`
`=> 2x+ 2= x-1`
`=>2x-x = -3`
`=> x= -3`
x+ 3/3 = x-1/2
=> x+ 1/ 1 = x-1/2
=> (x+1)2 =(x-1)1
=> 2x+ 2= x-1
=>2x-x = -3
=> x= -3
`x+ 3/3 = x-1/2`
`=> x+ 1/ 1 = x-1/2`
`=> (x+1)2 =(x-1)1`
`=> 2x+ 2= x-1`
`=>2x-x = -3`
`=> x= -3`
