2 câu trả lời
Ta có \(15abc0\div abc=1010\)
\(\left(15000+abc\right)\times10\div abc=\left(100+1\right)\times10\)
\(15000\div abc=100\)
\(abc=15000\div100\)
\(abc=150\)
Vậy\(a=1;b=5;c=0\)
Ta có \(15abc0\div abc=1010\)
\(\left(15000+abc\right)\times10\div abc=\left(100+1\right)\times10\)
\(15000\div abc=100\)
\(abc=15000\div100\)
\(abc=150\)
Vậy\(a=1;b=5;c=0\)
